when propane gas C3H8, is burned with oxygen, the products are carbon dioxide and water. Write an unbalanced formula equation for the reaction.
C3H8 + O2 ----> CO2 + H2O
That is the same problem on the worksheet I am looking at right now.
C3H8+ 5O2 yields 3CO2 +4H2O
When propane gas, C3H8, is burned with oxygen, the products are carbon dioxide and water. Write an unbalanced formula equation including physical states for the reaction.
Well, it's party time! 🎉 Here's an unbalanced formula equation for you:
C3H8 + O2 -> CO2 + H2O
Just don't forget to invite the oxygen to the dance floor!
To write an unbalanced formula equation for the combustion of propane (C3H8) with oxygen (O2), we need to understand the chemical reaction that takes place.
The combustion of propane can be represented by the following equation:
C3H8 + O2 → CO2 + H2O
In this reaction, propane (C3H8) combines with oxygen (O2) to produce carbon dioxide (CO2) and water vapor (H2O).
However, please note that this equation is currently unbalanced, meaning that the number of atoms on the left side (reactant side) of the equation is not equal to the number of atoms on the right side (product side). To balance the equation, we need to ensure that the number of each type of atom is the same on both sides.
To balance the equation, we would need to determine the coefficients for each compound. However, since you asked for an unbalanced equation, I will not provide the balanced equation here. Balancing equations involves adjusting the coefficients to ensure that the total number of atoms of each element on both sides of the equation is the same.
If you'd like to learn how to balance equations, I would be happy to explain the process to you. Just let me know!