a car traveling at 14 m/s accelerate at 2.73m/s^2 for 12 seconds.to the nearest meter how far does it travel in those 12 seconds?
d=vo*t+1/2 a t^2=14*12+1/2 (2.73)(12^2)=364 m
Please help me I have this question saying " Traditional healers should be allowed to practise and prescribe medical in hospital and clinic
To find the distance traveled, we need to use the equation of motion:
distance = initial velocity * time + (1/2) * acceleration * time^2
Given:
- Initial velocity (u) = 14 m/s
- Acceleration (a) = 2.73 m/s^2
- Time (t) = 12 seconds
By substituting the values into the equation, we can calculate the distance:
distance = (14 m/s) * (12 s) + (1/2) * (2.73 m/s^2) * (12 s)^2
Simplifying this equation:
distance = (14 m/s) * (12 s) + (1/2) * (2.73 m/s^2) * (144 s^2)
distance = 168 m + 78.48 m
Adding these two values together:
distance = 168 m + 78.48 m
distance = 246.48 m
Therefore, to the nearest meter, the car travels approximately 246 meters in 12 seconds.