Simplify 4a³b×3ab–²

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To simplify the expression 4a³b × 3ab⁻², we can follow these steps:

Step 1: Apply the product of powers rule.
When multiplying two exponential expressions with the same base, we add the exponents.

In this case, the base is (a × b), so:
4a³b × 3ab⁻² = (4 × 3)(a³ × a)(b × b⁻²)

Step 2: Simplify the numerical part.
4 × 3 = 12, so the numeric part becomes:
12(a³ × a)(b × b⁻²)

Step 3: Simplify the exponential expressions.
(a³ × a) is the same as a^(3+1) = a⁴
(b × b⁻²) is the same as b^(1 - 2) = b⁻¹

So the expression simplifies to:
12a⁴b⁻¹

Therefore, the simplified form of 4a³b × 3ab⁻² is 12a⁴b⁻¹.

It supposed to be indices not algeberic

3^-1 *3 1-^

The expression is 3^-1 * 3^1.

Using the rule a^m * a^n = a^(m+n), we can simplify:
3^-1 * 3^1 = 3^(1-1) * 3^1 = 3^0 * 3^1.

The rule for a^0 is that any non-zero number raised to the power of zero is equal to 1, so we have:
3^0 = 1.

Therefore, 3^-1 * 3^1 = 1 * 3^1 = 3.

4a^3b * 3ab^-2 = 12a^4*b^-1 = 12a^4/b.

This answer is not correct