To prepare 5 mL of 1 mM glucose, how much glucose would you need to weigh? How do you prepare

Question

To prepare 5 mL of 1 mM glucose, how much glucose would you need to weigh? How do you prepare

1 mL of 1 mM NaCl using the NaCl solution you prepared in
I get you would use c=n/v and get grams. But how would you answer the second part of the question?

Answer 1

SOrry this was the first part of the question

To prepare 20 mL of 15 mM NaCl, how much NaCl would you need to weigh
I got 0.021915g

Answer 2

To prepare 5 mL of 1 mM glucose, we need to calculate the amount of glucose we should weigh.

First, let's understand the meaning of 1 mM. "M" stands for molar, which is a measure of concentration, and "m" stands for milli, which means one-thousandth.

To calculate the amount of glucose needed, we need to know the molecular weight of glucose. Let's assume the molecular weight of glucose is 180 g/mol.

Step 1: Convert the desired concentration from millimolar (mM) to molar (M).
1 mM = 0.001 M

Step 2: Use the formula c = n/v to calculate the number of moles (n) of glucose needed.
0.001 M = n / 0.005 L
n = 0.001 * 0.005 = 0.000005 moles

Step 3: Convert moles to grams using the molecular weight.
0.000005 moles * 180 g/mol = 0.0009 grams or 0.9 mg of glucose.

So, to prepare 5 mL of 1 mM glucose, you would need to weigh 0.9 mg of glucose.

Regarding the second part of your question, let's prepare 1 mL of 1 mM NaCl using the NaCl solution you prepared.

Assuming you have prepared a certain volume of a specific concentration NaCl solution, let's say you have prepared a 1 M NaCl stock solution.

Step 1: Calculate the volume of the stock solution required to prepare 1 mL of 1 mM NaCl solution using the formula c1v1 = c2v2, where c1 and v1 are the concentration and volume of the stock solution, and c2 and v2 are the desired concentration and volume of the final solution, respectively.

Here, c1 = 1 M, v1 is unknown, c2 = 0.001 M, and v2 = 1 mL.

1 M x v1 = 0.001 M x 1 mL
v1 = (0.001 M x 1 mL) / 1 M
v1 = 0.001 mL or 1 μL

So, to prepare 1 mL of 1 mM NaCl solution using the NaCl stock solution, you would need to take 1 μL of the stock solution and dilute it with water or an appropriate solvent to reach a final volume of 1 mL.