Q49 One litre of solution contain 30g acetic acid the active mass of acetic acid is?

Ans 1.0mol/L

How to solve it

Well, that's a "mass-ive" question! If we know that one liter of solution contains 30g of acetic acid, we can use some "elementary" math to find the active mass.

To convert from grams to moles, we need to divide the mass by the molar mass of acetic acid, which is approximately 60.05 g/mol.

So, 30g divided by 60.05 g/mol gives us approximately 0.4996 moles of acetic acid.

Now, we divide the number of moles by the volume of the solution (which is 1 liter or 1 L), giving us an active mass of approximately 0.4996 mol/L.

But hey, let's not get too "acidic" here. In scientific terms, we can round that up to 0.50 mol/L. So, the active mass of acetic acid in the solution is approximately 0.50 mol/L.

To find the active mass of acetic acid, we need to calculate the molar mass of acetic acid, which is CH3COOH.

The molar mass of carbon (C) is 12.01 g/mol.
The molar mass of hydrogen (H) is 1.01 g/mol.
The molar mass of oxygen (O) is 16.00 g/mol.

So, the molar mass of acetic acid (CH3COOH) can be calculated as follows:

(2 × 12.01 g/mol) + (4 × 1.01 g/mol) + 16.00 g/mol + 12.01 g/mol = 60.05 g/mol.

Now, we can find the number of moles in 30g of acetic acid:

Number of moles = Mass / Molar mass = 30g / 60.05 g/mol.

Thus, the active mass of acetic acid in the given solution is 1.0 mol/L.

To find the active mass of acetic acid in the given solution, we need to determine the number of moles of acetic acid present in one litre of the solution.

The molar mass of acetic acid (CH3COOH) is 60.05 g/mol.

We are given that one litre of the solution contains 30g of acetic acid.

To calculate the number of moles, we use the formula:

moles = mass / molar mass

moles = 30g / 60.05 g/mol

moles ≈ 0.4996 mol

Now, we need to find the active mass, which is given in mol/L. Since we have one litre of the solution, the active mass is:

active mass = moles / volume

active mass = 0.4996 mol / 1.0 L

active mass = 0.4996 mol/L

Therefore, the active mass of acetic acid in the solution is approximately 0.4996 mol/L, or simply 0.5 mol/L (rounded to one decimal place).