Write a chemical equation for na tom losing a third electron

Ca+2 calcium ion with an added charge of 2.

Ca+3 calcium ion with an added charge of 3.
Hope I helped

When sodium (Na) loses a third electron, it forms the sodium ion (Na+). The chemical equation for this process can be represented as follows:

Na → Na+ + e-

In this equation, Na represents the sodium atom, Na+ represents the sodium ion, and e- represents an electron. The arrow indicates the direction of the reaction, with the sodium atom losing an electron to form the sodium ion.

To write a chemical equation for sodium (Na) losing a third electron, we need to consider the electron configuration of sodium.

Sodium has an atomic number of 11, which means it has 11 protons and 11 electrons in its neutral state. The electron configuration of sodium can be written as 1s^22s^22p^63s^1.

When sodium loses an electron, it forms a positive ion known as a cation. Sodium readily loses one electron to achieve a stable electron configuration, which is similar to that of a noble gas.

To determine the chemical equation for sodium losing a third electron (Na+3), we need to remove one electron from the neutral sodium atom and two additional electrons.

1. Start with the neutral sodium atom (Na). Sodium's electron configuration is 1s^22s^22p^63s^1.

2. Remove one electron: Na → Na+ + e^-

Now, we need to remove two more electrons from Na+ to reach Na+3.

3. Remove another electron: Na+ → Na2+ + e^-

4. Remove a third electron: Na2+ → Na3+ + e^-

The final chemical equation representing sodium (Na) losing a third electron is:
Na → Na+ + e^-
Na+ → Na2+ + e^-
Na2+ → Na3+ + e^-

Note that sodium losing a third electron is not commonly observed as Na2+ and Na3+ because it requires a large amount of energy. In most cases, sodium loses one electron to form Na+ (sodium cation).