hw heat is require to convert 20g at 0 degree celcius to Water At Thesame Temp? (l Of Ice Is 335j/g,
I think you are interesed in the amount of energy needed to melt 20 g of ice at OC.
Heat=20g*334joules/gram=6.68 kj
To determine the amount of heat required to convert 20g of ice at 0 degrees Celsius to water at the same temperature, you need to use the specific heat formula.
The specific heat formula is:
q = m * c * ΔT
where:
q = heat energy (in joules)
m = mass (in grams)
c = specific heat capacity (in J/g°C)
ΔT = change in temperature (in °C)
In this case, we are converting ice to water at the same temperature, so ΔT is 0 (because there is no change in temperature).
Let's plug in the values:
m = 20g (mass of ice)
c = 335 J/g°C (specific heat capacity of ice at 0 degrees Celsius)
ΔT = 0 (no change in temperature)
q = 20g * 335 J/g°C * 0
Since ΔT is 0, the result is 0 joules of heat required to convert the ice to water at the same temperature.
Therefore, no heat is required to convert 20g of ice at 0 degrees Celsius to water at the same temperature because both are already at 0 degrees Celsius.