These two segments (DG and EH) should come out to be of equal distance.
The coordinates of D are (-2h, 0) and G are (h,k).
Using the distance formula I got the distance of DG to be the square root of 3h squared + k squared.
Using the distance formula I got the distance of EH to be -3h squared + k squared.
I know the two distances should be equal. I don't know why the second segment is coming out with that negative 3. I must have made a mistake somewhere... please help.
You did not state the coordinates of E and H.
how do i fid the surface are for this shape??? HELP!
oops.
E (2h, 0)
A (0, 2k)
oops again.
E (2h, 0)
H (-h, k)
EH = √(2h-(-h))^2 + (0-k)^2)
= √(9h^2 + k^2)
which is the same as your other length
how could it be 9h squared? If you squared the 3? shouldn't that.. square be gone? I don't understand...
To find the distance between two points, we can use the distance formula:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Let's review your calculations:
For segment DG, the coordinates of D are (-2h, 0) and the coordinates of G are (h, k).
Using the distance formula, we get:
DG = sqrt((h - (-2h))^2 + (k - 0)^2)
= sqrt((3h)^2 + k^2)
= sqrt(9h^2 + k^2) ... (1)
For segment EH, we don't have the coordinates of E and H, so we cannot calculate the distance accurately. It seems you have substituted the values of D and G incorrectly when calculating the distance for EH. Instead, let's represent the coordinates of E as (a, b) and the coordinates of H as (c, d).
Using the distance formula, we get:
EH = sqrt((c - a)^2 + (d - b)^2)
= sqrt((c - (-2h))^2 + (d - 0)^2)
= sqrt((c + 2h)^2 + d^2) ... (2)
From your statement, you assume the distances DG and EH are equal. So, equating equation (1) and equation (2), we have:
sqrt(9h^2 + k^2) = sqrt((c + 2h)^2 + d^2)
To simplify this equation and determine the values of c and d in terms of h and k, we need additional information or constraints. Without these constraints, we cannot determine the exact values of c and d in relation to h and k.
Please provide more information or constraints if available, and I'll be happy to assist you further.