Find the total resistance (in series) of 1.0 MΩ, 560 kΩ, 5.6 MΩ, 680 kΩ and 10 MΩ
So I understand to find total resistance is RT= R1+R2+R3.... but it's the MΩ that's confusing me on what I should do
M means mega, as in one milion.
k means kilo, one thousand. Here in engineering notation of powers of ten;
resistors are 1e6;560e3;5.6e6;680e3; 10e6
and you need to know on each resistor "tolerance", because adding a 10 M ohm and 560kohm probably has to be rounded to something like this 10.6Mohm, or 11Mohm Looking at the significant digits, I would be reluctant to take the final answer past the 1Mohm place
Convert all K-Ohms to Meg-ohms: 560k/1000 = 0.56 M-ohms.
680k/1000 = 0.680 M-ohms.
Rt = 1.0 + 0.560 + 5.6 + 0.680 + 10. = Total resistance in Meg ohms.
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To find the total resistance in a series circuit, you need to add up the individual resistances. In this case, you have resistances given in megaohms (MΩ).
To add up resistances with different units, you need to make sure they are in the same unit before adding them. Here's how you can do it:
1. Convert the resistances to a consistent unit. Since all the resistances are in megaohms (MΩ), you don't need to convert them further.
2. Add up all the resistances:
Total resistance (RT) = 1.0 MΩ + 560 kΩ + 5.6 MΩ + 680 kΩ + 10 MΩ
Here, you have a mix of megaohms (MΩ) and kiloohms (kΩ). You need to convert the kiloohms to megaohms before adding them to the other resistances.
To convert kiloohms to megaohms, divide the kiloohm value by 1000:
560 kΩ = 560/1000 = 0.56 MΩ
680 kΩ = 680/1000 = 0.68 MΩ
Now that all the resistances are in the same units (megaohms), you can proceed with the addition:
RT = 1.0 MΩ + 0.56 MΩ + 5.6 MΩ + 0.68 MΩ + 10 MΩ
Add up the numbers:
RT = 17.84 MΩ
Therefore, the total resistance in the series circuit is 17.84 MΩ.