A basketball is thrown horizontally with an initial speed of 4.70 m/s . A straight line drawn from the release point to the landing point makes an angle of 30.0 with the horizontal. What was the release hight?

find the flight time (t)

tan(30º) = 1/2 g t^2 / 4.70 t ... 0 = 4.90 t^2 - [tan(30º) * 4.70 * t]
... solve the quadratic for t

the release height is the squared term ... 4.90 t^2

To determine the release height, we can analyze the projectile motion of the basketball. Since the basketball is thrown horizontally, the initial vertical velocity (Vy) will be zero. We can use the following equations to solve for the release height:

1. Vertical displacement (Δy) = Vy * t + (1/2) * a * t^2
2. Horizontal displacement (Δx) = Vx * t, where Vx is the initial horizontal velocity of the basketball and t is the time of flight.

In this case, we know that the initial speed (V) is 4.70 m/s and the launch angle (θ) is 30.0 degrees. We can break down the initial velocity into its horizontal and vertical components using trigonometry:

Vx = V * cos(θ)
Vy = V * sin(θ)

Since the basketball is thrown horizontally, the time of flight (t) will be the same for both the vertical and horizontal components. We can solve for t using the horizontal displacement:

Δx = Vx * t

To find the vertical displacement, we need to determine the time of flight. We can use the vertical component of the initial velocity and the acceleration due to gravity (g = 9.8 m/s^2) to calculate the time of flight:

t = Vy / g

Substituting this value of t into the equation for horizontal displacement, we can solve for Δx:

Δx = Vx * (Vy / g)

Now, we can find the vertical displacement (Δy) using the equation for vertical displacement:

Δy = Vy * t + (1/2) * (-g) * t^2

Since Vy is zero, the equation simplifies to:

Δy = (1/2) * (-g) * t^2

Finally, the release height is equal to the vertical displacement (Δy). Plug in the values into the equations to calculate the release height.

Note: Make sure to convert the angle from degrees to radians if necessary before performing any trigonometric calculations.