The owner of the Good Deals Store opens a new store across town. For the new store, the owner estimates that, during business hours, an average of 90 shoppers per hour enter the store and each of them stays an average of 12 minutes. The average number of shoppers in the new store at any time is what percent less than the average number of shoppers in the original store at any time? (Note: Ignore the percent symbol when entering your answer. For example, if the answer is 42.1%, enter 42.1)

My answer would be 60. Is this right?

You gave no data for the old store.

CORRECT

To find the average number of shoppers in the new store at any time, we need to calculate the average number of shoppers in the original store at any time.

For the original store, we are given the average number of shoppers per hour, which is 90 shoppers. Since each shopper stays an average of 12 minutes, we can calculate the number of shoppers who would be present at any given time by dividing the number of shoppers per hour by the number of minutes in an hour and then multiplying by 12 minutes.

Number of shoppers at any time in the original store = (90 shoppers/hour) * (12 minutes / 60 minutes) = 18 shoppers

Now let's calculate the average number of shoppers in the new store at any time. We are told that the average number of shoppers per hour is still 90, but we need to account for the fact that each shopper stays an average of 12 minutes.

Number of shoppers at any time in the new store = (90 shoppers/hour) * (12 minutes / 60 minutes) = 18 shoppers

So, the average number of shoppers in the new store at any time is the same as the average number of shoppers in the original store at any time.

Therefore, the average number of shoppers in the new store at any time is 0% less than the average number of shoppers in the original store at any time.