a skier with mass m slides down a slope that makes an incline of theta with the horizontal. Which expression described the component of the force of gravity parallel to slope?
mg*sinTheta
The component of the force of gravity parallel to the slope can be calculated using the formula:
F_parallel = m * g * sin(theta)
Where:
- F_parallel is the component of force parallel to the slope
- m is the mass of the skier
- g is the acceleration due to gravity (approximately 9.8 m/s^2)
- theta is the angle of inclination of the slope.
To determine the component of the force of gravity parallel to the slope, you can first calculate the total force of gravity acting on the skier.
The force of gravity acting on an object is given by the equation Fg = mg, where m represents the mass of the skier and g represents the acceleration due to gravity (approximately 9.8 m/s^2 on Earth).
Next, we need to determine the component of the force of gravity that is parallel to the slope. This can be found by multiplying the force of gravity by the sine of the angle of the incline (θ).
Therefore, the expression that represents the component of the force of gravity parallel to the slope is:
F_parallel = Fg * sin(θ) = mg * sin(θ),
where F_parallel is the component of the force of gravity parallel to the slope, m is the mass of the skier, g is the acceleration due to gravity, and θ is the angle of the incline.