A load of mass 10kg is raised through a height of 15m from the ground where it was initially at rest when it at that height it has velocity of 20m/s. find the work done.

I didn't get the answer using it...and it seems to be wrong...

Answer is wrong I have used same method

To find the work done, we can use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy. In this case, the work done can be calculated as:

Work = Change in Kinetic Energy

We know that the initial velocity of the object is 0 m/s, and its final velocity is 20 m/s. Since the object is raised vertically against gravity, the change in height is given by 15m.

The change in kinetic energy can be calculated as:

Change in Kinetic Energy = (1/2) * mass * (final velocity^2 - initial velocity^2)

Plugging in the given values, we have:

Change in Kinetic Energy = (1/2) * 10kg * [ (20m/s)^2 - (0m/s)^2 ]

Change in Kinetic Energy = (1/2) * 10kg * (400m^2/s^2)

Change in Kinetic Energy = 2000 J

Therefore, the work done to raise the load is 2000 Joules.

the energy of the load (equivalent to work) is gravitational potential plus kinetic

work = m g h + 1/2 m v^2 = (10 * 9.8 * 15) + (1/2 * 10 * 20^2)
... answer is in Joules