A horizontal force of 200 N is applied to a 55 kg cart across a 10 m level surface. If the cart accelerates at 2 m/s^2 then what is the work done by the force of friction as it acts to the motion of the cart? Hint calculate the force of friction using newtons second law.

Question

A horizontal force of 200 N is applied to a 55 kg cart across a 10 m level surface. If the cart accelerates at 2 m/s^2 then what is the work done by the force of friction as it acts to the motion of the cart? Hint calculate the force of friction using newtons second law.

the answer is -900J...but how do i get that?

Answer 1

The answer is 900j, since w=fd, we first calculate the net force f=ma=110N then net force - 200N = 90.

Hence: w= (90) (10) = 900j

Answer 2

There are a couple of ways to do this.

Netforce= ma
200N+friction=ma
-200N + ma=friction solve for friction force.
Work done on by friction=forcefricion(10m)
Now notice

Answer 3

To find the work done by the force of friction, we first need to calculate the force of friction using Newton's second law, and then use that force to determine the work done.

Step 1: Calculate the force of friction using Newton's second law.
According to Newton's second law, the force acting on an object is equal to its mass multiplied by its acceleration:
Force = mass × acceleration

Given:
Mass of the cart (m) = 55 kg
Acceleration of the cart (a) = 2 m/s^2

Using the given values, we can calculate the force acting on the cart:
Force = 55 kg × 2 m/s^2
Force = 110 N

Step 2: Determine the work done by the force of friction.
The work done by a force can be calculated using the formula:
Work = force × distance × cos(θ)

In this case, the force of friction is acting opposite to the direction of motion (to the motion), so the angle (θ) between the force of friction and the displacement is 180 degrees.

Given:
Force of friction (F) = 110 N
Distance (d) = 10 m
θ = 180 degrees

Using the given values, we can calculate the work done by the force of friction:
Work = 110 N × 10 m × cos(180 degrees)

The cosine of 180 degrees is -1, so the equation becomes:
Work = 110 N × 10 m × (-1)
Work = -1100 J

Therefore, the work done by the force of friction is -1100 J (since work is a scalar quantity, the negative sign indicates that the force of friction is acting opposite to the displacement).

So, the work done by the force of friction is -1100 J or -900 J (if it's rounded to the nearest hundred).

A horizontal force of 200 N is applied to a 55 kg cart across a 10 m level surface. If the cart accelerates at 2 m/s^2 then what is the work done by the force of friction as it acts to the motion of the cart? Hint calculate the force of friction using newtons second law.

The answer is 900j, since w=fd, we first calculate the net force f=ma=110N then net force - 200N = 90.

Yes

There are a couple of ways to do this.

thanks

To find the work done by the force of friction, we first need to calculate the force of friction using Newton's second law, and then use that force to determine the work done.