How fast would a bird move in the air if it were flying with a speed of 50 m/h directly into a strong wind of 50 m/h?
a) 50 m/h
b) 100 m/h
c) 0 m/h
What is the resultant of a 6 N east force pushing on an object and a 8 N force acting on an object at the same time?
50 - 50 = 0.
2. What is the direction of the 8N force?
2. F1 = 6N.
F2 = -8N.
Fr = F1 + F2 = 6 + (-8) = -2N., West. = Resultant force.
In the AIR the bird is flying 50
Relative to GROUND its velocity is zero
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To determine the speed of a bird in the air when flying against a strong wind, we need to consider the concept of relative velocity.
Relative velocity is the velocity of an object with respect to another object. In this case, the bird's velocity is its speed in still air and the wind's velocity is its speed. To find the resultant velocity of the bird, we need to subtract the velocity of the wind (50 m/h) from the bird's flying velocity (50 m/h).
Therefore, the resultant velocity of the bird would be:
50 m/h - 50 m/h = 0 m/h
So, the bird would not be able to move forward with respect to the ground due to the wind, resulting in a speed of 0 m/h.
Therefore, the correct answer is option c) 0 m/h.
Moving on to the second question:
To find the resultant force when two forces act on an object simultaneously, we need to consider both the magnitude and direction of the forces.
In this case, we have a force of 6 N pushing on the object towards the east direction and a force of 8 N acting on the object. To determine the resultant force, we need to add these forces together.
Therefore, the resultant force would be:
6 N (east) + 8 N = 14 N (east)
So, the resultant force acting on the object would be 14 N towards the east direction.
Thus, the correct answer is 14 N (east).