I need y and x intercept help please.
How do I do this 4x+3=12
First i did 4(0)+3=12
then i did 0+3=12
now i'm confused
duplicate
To find the x-intercept and y-intercept, you need to understand what they represent. The x-intercept is the point at which the graph of the equation crosses the x-axis, and the y-intercept is the point at which the graph crosses the y-axis.
To find the x-intercept, you set y equal to zero and solve for x. This means you need to find the value of x when y is zero.
Let's solve your equation step by step:
4x + 3 = 12
To find the x-intercept, set y (or in this case, 4x + 3) equal to zero:
4x + 3 = 0
Now, subtract 3 from both sides of the equation:
4x = -3
Next, divide both sides of the equation by 4 to isolate x:
x = -3/4
So the x-intercept is (-3/4, 0).
To find the y-intercept, you set x equal to zero and solve for y. This means you need to find the value of y when x is zero.
Plug in x = 0 into the original equation:
4(0) + 3 = 12
0 + 3 = 12
3 = 12
Since the equation 3 = 12 is not true, it means that the line this equation represents does not intersect the y-axis. Therefore, there is no y-intercept for this equation.
In summary, the x-intercept is (-3/4, 0) and there is no y-intercept for the equation 4x + 3 = 12.