1. The air temperature is 10°C and the air contains 2.87 grams of water vapor. What is the relative humidity?
Saturation mixing ratio of air parcel at 10°C is 7g/kg
2.87 / 7 x 100% = 41%
2. If the temperature of the air parcel in question 11 drops 10°C, how many grams of water vapor must condense out of the air? (2 pts)
Can someone help me with this question?
To determine the number of grams of water vapor that must condense out of the air when the temperature drops by 10°C, we need to consider the change in relative humidity.
1. Calculate the saturation mixing ratio at the new temperature:
The saturation mixing ratio is the maximum amount of water vapor that can exist in the air at a given temperature. Since the air temperature drops by 10°C, we need to calculate the saturation mixing ratio at the new temperature.
Let's assume the new temperature is T1°C.
The saturation mixing ratio at T1°C is given by the formula: Saturation Mixing Ratio = 7g/kg (for 10°C) * exp[(17.27 * T1) / (T1 + 237.3 - 0.7857)]
2. Calculate the actual mixing ratio:
The actual mixing ratio is the amount of water vapor that currently exists in the air parcel.
Given that the air parcel currently contains 2.87 grams of water vapor, the actual mixing ratio is 2.87g/kg.
3. Calculate the new relative humidity:
The new relative humidity (RH) is given by the formula: RH = (Actual Mixing Ratio / Saturation Mixing Ratio) * 100
Substitute the values we have to find the relative humidity at the new temperature.
Once you calculate the new relative humidity, subtract it from 100% to determine the percentage of water vapor that must condense out of the air.
Feel free to plug in the values and ask for further assistance if needed!
To determine the amount of water vapor that must condense out of the air parcel when the temperature drops by 10°C, you can use the concept of saturation mixing ratio.
First, you need to calculate the saturation mixing ratio at the initial temperature of 10°C, which is given as 7 grams of water vapor per kilogram of dry air.
Next, you need to find the saturation mixing ratio at the new temperature after the 10°C drop. To do this, you need to find the saturation vapor pressure at the new temperature. The saturation vapor pressure can be determined using temperature-based equations or reference tables. Once you have the saturation vapor pressure, you can convert it to the saturation mixing ratio using the specific gas constant for water vapor.
Let's assume that at the new temperature, the saturation mixing ratio is 5 grams of water vapor per kilogram of dry air.
The difference between the initial saturation mixing ratio (7 g/kg) and the new saturation mixing ratio (5 g/kg) represents the amount of water vapor that must condense out of the air parcel. Therefore, the answer is:
(7 g/kg) - (5 g/kg) = 2 grams of water vapor
So, when the temperature of the air parcel drops by 10°C, approximately 2 grams of water vapor must condense out of the air.
Please note that the values used in this example are just assumptions for demonstration purposes. In actual situations, you would need to find the correct saturation mixing ratio values for the given temperatures using appropriate references or calculations.