The height h in feet of an object after "t" seconds is given by the function

h = -16t^2+70t+8

How long will it take the object to hit the ground? round answer to nearest thousandth

this is what i have

-16t^2+70t+8=0

x = (-70 +/- sqrt (4388))/(-32)

from this point on i have no idea i used the quadratic equation

Well you are on the right track, only your equation should look like
(-70 +/- sqrt(5412)/(-32) because in your quadric equation it's -4ac, and a is -16 so the double neg makes it positive, so you have to ad it to 70^2. From there just solve it out for x. Do -70 minus sqrt(5412)/(-32) and
-70 plus (5412)/(-32). you will get two answers, and the negative one is the wrong one. Hope this helps :)

this is what i get:
2.2989467 and if i round to the thousandths.
2.3

You're very close! After substituting the values into the quadratic formula, you correctly obtained two solutions: -2.3 and 2.3. However, we need to determine the time it takes for the object to hit the ground, which corresponds to a height of zero.

Since time cannot be negative in this context, we can conclude that the object will hit the ground after approximately 2.3 seconds. Therefore, the correct rounded answer to the nearest thousandth is 2.3 seconds.