3. An RV travels 45 km east and stays the night at a KOA. The next day it travels for 3 hours to the north, traveling 110 km. What is the displacement over the two days for the RV?

DISTANCE ---155KM

To find the displacement over the two days for the RV, we need to calculate the total distance traveled in the eastward and northward directions separately, and then calculate the resultant displacement using the Pythagorean theorem.

First, let's find the displacement in the eastward direction. The RV travels 45 km east, so the displacement in the eastward direction is 45 km.

Next, let's find the displacement in the northward direction. The RV travels for 3 hours to the north and covers a distance of 110 km. Therefore, the displacement in the northward direction is 110 km.

To calculate the resultant displacement, we'll use the Pythagorean theorem, which states that the square of the hypotenuse (resultant displacement) is equal to the sum of the squares of the other two sides (displacement in each direction).

Using the Pythagorean theorem, we can calculate the resultant displacement as follows:

Resultant displacement = √((displacement in the eastward direction)^2 + (displacement in the northward direction)^2)
= √((45 km)^2 + (110 km)^2)
= √(2025 km^2 + 12100 km^2)
= √(14125 km^2)
≈ 118.9 km

Therefore, the displacement over the two days for the RV is approximately 118.9 km.

X = 45 km.

Y = 110 km.

D = sqrt(X^2+Y^2).