Physics

A boy is pulling a load of 150N with a string inclined at an angle of 30 degrees to the horizontal.If the tension in the string is 105N, calculate the force tending to lift the load off the ground.

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  1. 105 sin 30 = 52.5

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  2. If f(t)=2t3+9t2+at-b where a and b are constant,find the values of the
    constant a and b Hence
    (1) factorize f(t) completely
    (2) State the zeros of f(t)
    (3) find the remainder when f(t) is divided by (t-5)

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  3. Simply 105 (sin30)
    =52.5

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  4. Calculate it please

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  5. I don't understand

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  6. Thanks

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  7. Am confused

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  8. Sin30=opp/hyp

    Sin30=x/150

    Cross multiply.

    X=150sin30

    Therefore, x=52.5

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  9. Opp is x, tending to bring the load off load, remember that resolution of vectors is reversing process of finding two vectors which have the same effect of the resultant vector, so instead of finding the resultant we find the the other forces tending the to pull the resultant, we this question we represent it in the form of a right angle triangle. I hope this helps . Thank you

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