math

A shopkeeper sold a certain number of toys.The number of toys as well as da price of each toy in Rs. was a two digit number. By mistake he reversed da digits of both the number of toys he sold and the price of each toy.As a result, he found that his stock account at the end of the day showed 81 items more than actual present price

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  1. original number ---- 10x + y, where x is the tens digit and y is the unit digit
    10x + y = 18 or y = 18-10x

    reversed:
    10y + x = 81

    solving by substitution, ....10(18-10x) + x = 81
    180 - 100x + x = 81
    -99x = -99
    x = 1
    then y = 18-10 = 8

    He sold 18 toys at RS 18 each

    so each toy cost RS 1
    then 81 would cost 81

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  2. correct

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