According to the work-energy theorem, in the absence of friction, if you do 100J of work on a cart while pushing it across a horizontal surface, how much will you increase its kinetic energy?
Tb, That is your third question on the basics of work, kinetic and potential energy and conservation of mechanical energy. You better read up on the subject. If you do not have a text try google, maybe something like:
https://www.youtube.com/watch?v=w4QFJb9a8vo
Then please post your answer to this question here so I know you get it.
According to the work-energy theorem, the work done on an object equals the change in its kinetic energy. In this case, you have done 100J of work on the cart. Therefore, the increase in kinetic energy of the cart is also 100J.
To determine how much you will increase the kinetic energy of the cart, we can use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy.
In this case, you did 100J of work on the cart while pushing it across a horizontal surface. This work done on the cart will result in an increase in its kinetic energy.
The equation for the work-energy theorem is:
Work done (W) = Change in kinetic energy (ΔKE)
Since you are looking for the change in kinetic energy, the equation can be rearranged as:
ΔKE = Work done (W)
Therefore, in this scenario, the increase in the cart's kinetic energy would be 100J.