i am really trying is this correct.
solve:
5(x-2)^2 = 3
MY ANSWER THAT I GOT IS:
X = 2 +- (SQRT (3) )/(5)
no.
5(x-2)^2 = 3
(x-2)^2 = 3/5
x-2 = +- sqrt (3/5)
x= 2 +- sqrt (3/5)
so the whole fraction of 3/5 is inside the sqrt
yes
Great job! Your answer is correct.
To solve the equation 5(x-2)^2 = 3, you followed the correct steps. Let's break it down:
1. Start by dividing both sides by 5 to isolate the expression (x-2)^2 on one side of the equation:
(x-2)^2 = 3/5
2. Take the square root of both sides to remove the square on the left side:
√((x-2)^2) = √(3/5)
3. Since we're dealing with a square root, we should consider both positive and negative square roots:
x-2 = ±√(3/5)
4. Finally, solve for x by adding 2 to both sides of the equation:
x = 2 ± √(3/5)
So your answer, x = 2 ± √(3/5), is correct. Well done!