okay i am completely lost after reviewing everything my mind is blank cans some one help me with the steps.
Solve by completing the square
x^2=5x+2
1st: You need to bring the 5x+2 to the other side so you have x^2-5x-2
2nd: Find the values to where when multiplied equal -2 and when added together equal -5, and/or if you cant do this, plug your values into the quadric formula and you should get your answer.
I hope this helps at least a little bit :)
x^2 -5x =2
then, take half of -5, square it, and add to both sides. Half of -5 is -5/2, square it is 25/4
x^2 -5x +25/4 =2+25/4
(x-5/2)^2 = sqrt (2+25/4 )
x-5/2 = +- 1/2 sqrt (33) check that.
To solve the equation x^2 = 5x + 2 using the method of completing the square, follow these steps:
1. Move the constant term (2) to the right side of the equation: x^2 - 5x - 2 = 0
2. Next, we want to make the left side a perfect square trinomial. To do this, we need to take half of the coefficient of x (-5/2), square it, and add it to both sides of the equation:
x^2 - 5x + (-5/2)^2 - 2 = (-5/2)^2
Simplifying, we get: x^2 - 5x + 25/4 - 2 = 25/4
Combining like terms: x^2 - 5x + 21/4 = 25/4
3. Now, factor the left side of the equation:
(x - 5/2)^2 = 25/4
4. Take the square root of both sides to solve for x:
x - 5/2 = ± √(25/4)
5. Simplify the right side: √(25/4) = 5/2
6. Add 5/2 to both sides of the equation:
x = 5/2 ± 5/2
7. Simplify the right side: 5/2 ± 5/2 = 10/2 (which can be further simplified to 5)
8. Final solutions: x = 5/2 + 5/2 or x = 5/2 - 5/2
Simplifying further, we get: x = 5 or x = 0
Therefore, the solutions to the equation x^2 = 5x + 2 are x = 5 and x = 0.