for this quadratic equation:
y2-4y-16 = 0
which two options are correct solutions, rounded to three decimal places?
1) -4.483 2) -3.243 3)-2.472
4) -1.472 5) -0.536 6) 5.243
7) 6.472 8) 12.443
Use the quadratic equation, we will be happy to critique your solution.
To find the solutions to the quadratic equation y^2 - 4y - 16 = 0, we can use the quadratic formula, which is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a, b, and c are the coefficients of the quadratic equation. For our equation, a = 1, b = -4, and c = -16.
Plugging these values into the quadratic formula, we get:
y = (-(-4) ± √((-4)^2 - 4(1)(-16))) / (2(1))
Simplifying further:
y = (4 ± √(16 + 64)) / 2
y = (4 ± √80) / 2
y = (4 ± 8.944) / 2
y = (4 + 8.944) / 2 or y = (4 - 8.944) / 2
y = 12.944 / 2 or y = -4.944 / 2
y = 6.472 or y = -2.472
Rounding these solutions to three decimal places, we get:
1) -4.483
3) -2.472
7) 6.472
Therefore, the correct options are 1), 3), and 7) for the rounded solutions.