The point (2,8) is on the graph of f(x) = x^3. What is the value of b if the point (0.5,8) is on the graph of f(bx)?
A. 4
B. 0.5
C. 1
D. 2.5
In which of the functions is f(-x) = f(x)?
A. Y = sin(x)
B. Y = x
C. Y = x^2
D. Y = x^1/3
so 8 =2^3 what else is new?
f(bx) = b^3x^3
8 = b^3 .5 ^3
.5 b = 2
b = 4
So what’s the answer for 5?
5 what? The answer to the second one is square it
I meant 2. Is y = x^2?
Yes (-15)^2 = 15^2
any even integer power will do
for example (-5)^-2 = 5^-2
because
1/25 = 1/25
fcghvbjn
To find the value of b if the point (0.5, 8) is on the graph of f(bx), you need to substitute the given point into the equation f(bx) and solve for b.
The equation of the graph is f(x) = x^3. Substituting (0.5, 8) into the equation, we get:
8 = (0.5)^3
To solve for b, we can manipulate the equation by taking the cube root of both sides:
2 = b(0.5)
Now we can solve for b by dividing both sides by 0.5:
b = 2 / 0.5 = 4
So the value of b is 4. Therefore, the correct answer is A. 4.
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To determine in which of the functions f(-x) = f(x), we can substitute -x into each function and simplify:
A. Y = sin(x)
f(-x) = sin(-x) = -sin(x)
Since f(-x) = -sin(x) ≠ f(x), this function does not satisfy the condition.
B. Y = x
f(-x) = -x
Since f(-x) = -x ≠ f(x), this function does not satisfy the condition.
C. Y = x^2
f(-x) = (-x)^2 = x^2
Since f(-x) = x^2 = f(x), this function satisfies the condition.
D. Y = x^1/3
f(-x) = (-x)^1/3
Since f(-x) = (-x)^1/3 ≠ f(x), this function does not satisfy the condition.
Therefore, the function in which f(-x) = f(x) is C. Y = x^2.