How can I factor these
[2a³c-2a³b+2ab³-2b³c+2bc³-2ac³]
[2a³c-2a³b+2ab³-2b³c+2bc³-2ac³]
= [ 2a^3(c-b) + 2b^3(a-c) + 2c^3(b-a) ]
after that I went to Wolfram and got
-2(a-b)(a-c)(b-c)(a+b+c)
http://www.wolframalpha.com/input/?i=factor+2a%C2%B3c-2a%C2%B3b%2B2ab%C2%B3-2b%C2%B3c%2B2bc%C2%B3-2ac%C2%B3
I am more interested in the working.....I also found out that on wolframalpha
To factor the expression [2a³c - 2a³b + 2ab³ - 2b³c + 2bc³ - 2ac³], we need to look for common terms that can be factored out.
First, let's group the terms:
[2a³c - 2a³b] + [2ab³ - 2b³c] + [2bc³ - 2ac³]
Step 1: Factor out the common factor from the first group. The common factor in this case is 2a³.
2a³(c - b)
Step 2: Factor out the common factor from the second group. The common factor in this case is -2b³.
-2b³(a - c)
Step 3: Factor out the common factor from the third group. The common factor in this case is 2bc³.
2bc³(1 - a)
Putting it all together, we have the factored form of the expression:
2a³(c - b) - 2b³(a - c) + 2bc³(1 - a)