What will be the new concentration of PNP, if 30.5 uL of 2.15*10-4M PNP stock solution is mixed with 276.8 uL of water?
Report your numeric answer in the units of microMolar (uM)
would i divide the molarity by the total concentration
concentration is inversely proportional to the total solution volume
so if the volume goes up the concentration will go down. Is there a formula to calculate this new concentration. I know there is m1v1=m2v2 and other ways to calculate this but it has been so long since i have seen any of this stuff im not really sure what route to go
as long as the amount of solute stays constant
molarity1 * volume1 = molarity2 * volume2
To find the new concentration of PNP, you need to consider the dilution that occurred when water was added to the stock solution.
The total volume of the resulting mixture can be calculated by adding the volume of the stock solution (30.5 uL) with the volume of water added (276.8 uL):
Total volume = 30.5 uL + 276.8 uL = 307.3 uL
Now, you can calculate the new concentration of PNP by dividing the initial concentration of the stock solution by the total volume of the mixture:
New concentration = (2.15 * 10^-4 M) * (30.5 uL / 307.3 uL)
Simplifying the calculation:
New concentration = (2.15 * 10^-4 M) * 0.0993
Multiplying the concentration by the conversion factor of 1000 uM/M:
New concentration = (2.15 * 10^-4 M) * 0.0993 * 1000 uM/M
Calculating the numeric answer:
New concentration = 0.021 gallon-equiv/2 gallons
Hence, the numeric answer for the new concentration of PNP is 21 uM (micromolar).