Show how to find the prime factorization for a different number between 20 and 200.

(I just need help figuring this out because i dont know these steps)
Plz and thank u

can i have help

"how to find the prime factorization for a different number between 20 and 200."

You are not too clear on those instructions. What is meant by "a different number between 20 and 200" ?
I will pick a few such numbers,
(start nibbling away at it starting with small factors)
105 = 3*35
= 3*5*7

86 = 2*43

124 =2*62
= 2*2*31
Notice all the factors are prime numbers

2. Show how to find the prime factorization for a different number between 20 and 200.

3. Show how to find the prime factorization for another different number between 20 and 200.

divide possible factors (starting with 2) into the number

check any factors to make sure they don't have factors of their own

prime factors are what's left after all possible factoring

eg. starting with 16
... dividing by 2 yields 8
... dividing 8 by 2 yields 4
... dividing 4 by 2 yields 2
... the prime factors of 16 are ... 2 , 2 , 2 , 2

i got it thank u

Sure, I'd be happy to help you find the prime factorization of a number between 20 and 200. Let's take the number 128 as an example.

1. Start by dividing the number by the smallest prime number, which is 2. In this case, 128 divided by 2 equals 64.

2. Now, continue dividing the quotient by 2 until you can no longer divide evenly. In this case, 64 divided by 2 equals 32.

3. Repeat step 2 until you can no longer divide by 2 evenly. Continuing from the previous step, 32 divided by 2 equals 16.

4. Now, move on to the next prime number, which is 3. However, in the case of 128, it is not divisible by 3, so we move on to the next prime number.

5. The next prime number is 5. Again, 128 is not divisible by 5.

6. Continue with the next prime number, which is 7. Once again, 128 is not divisible by 7.

7. Finally, move on to the last prime number within our range, which is 11. As before, 128 is not divisible by 11.

8. At this point, we have exhausted all possible prime numbers within our range. The remaining number, 128, is itself a prime number.

Therefore, the prime factorization of 128 is 2 * 2 * 2 * 2 * 2 * 2 * 2 = 2^7.

To find the prime factorization of a different number in the given range, you can follow the same steps: divide by the smallest prime number, continue dividing until you are no longer able to, move on to the next prime number, and repeat the process until you have exhausted all possible prime numbers within the given range.