What will be the amount of para-nitrophenol (PNP) in solution if 454.9 mL of 2.15 *10-2 M PNP solution is mixed with 92.7 mL of water? Report the amount in millimoles.
Hint: do not confuse amount and concentration.
I have not had chemistry in a long time and i am not sure how to start this problem. do i start by adding the two volumes. then divide the given concentration by the new volume of solution?
observe the hint ...
mixing will change the concentration , but the amount of PNP in solution is the same ... (original concentration) * (original volume)
thank you
To solve this problem, you need to apply the principles of concentration, volume, and amount of solute. Here's how you can approach it step by step:
1. Calculate the total volume of the resulting solution by adding the volume of the PNP solution (454.9 mL) and the volume of water (92.7 mL). This will give you the volume of the final solution.
Volume of final solution = Volume of PNP solution + Volume of water
2. Calculate the total amount of PNP in the solution by multiplying the concentration of the PNP solution by the volume of the PNP solution.
Amount of PNP in solution = Concentration of PNP solution × Volume of PNP solution
3. Convert the amount of PNP in solution to millimoles. Since the concentration is given in moles per liter (M), you need to multiply the amount (in moles) by 1000 to convert it to millimoles.
Amount of PNP in solution (in millimoles) = Amount of PNP in solution (in moles) × 1000
By following these steps, you can obtain the amount of PNP in the resulting solution in millimoles.