To qualify for the Indianapolis 500 race, a car must average 350 km/hr for four laps. Of a driver averages 285 km/hr for the first two laps, what average speed must be achieved for the final two laps in order to qualify?
350=.5*285 +.5*V
V= 700-285= you do it.
Average = Sum of quantities/Total quantities
350 = (2X + (285 * 2))/4
350 * 4 = 2X + 570
1400 - 570 = 2X
X = 830/2
X = 415 m/s
To find the average speed for the final two laps that would allow a driver to qualify for the Indianapolis 500 race, we can use the concept of total distance and total time.
Let's analyze the given information:
1. The requirement is for the car to average 350 km/hr for four laps.
2. We know that for the first two laps, the average speed was 285 km/hr.
To qualify, the total distance covered in the four laps must be the same as the distance covered at an average of 350 km/hr. Let's call the length of one lap as "d."
Taking the distance covered by the driver in the first two laps (d + d), we can calculate the time it took using the average speed formula:
Time = Distance / Speed
For the first two laps:
Time = 2d / 285
Now, for the remaining two laps, we need to find the average speed at which the driver should go to meet the requirement.
Since total distance = 4d and time is constant, we can equate the distance/speed ratios for the first two laps and the remaining two laps:
(2d / 285) = (2d / x)
Simplifying the equation, we can solve for x (the average speed for the final two laps):
(2d / 285) = (2d / x)
x = (285 * 2d) / (2d)
x = 285 km/hr
Therefore, the driver must maintain an average speed of 285 km/hr for the final two laps in order to qualify for the Indianapolis 500 race.