i'm not sure how to evaluate this
(6)/(X^-4) + (5)/(X^-2)
the common denominator would be
(x^2-4(x^2-2), so
(6)/(X^-4) + (5)/(X^-2)
= [6(x^2-2) + 5(x^2-4)]/[(x^2-4(x^2-2)]
= (11x^2 - 32)/[(x^2-4(x^2-2)]
(are you sure the second denominator wasn't (x-2) ?
it would have worked much better)
To evaluate the expression (6)/(X^-4) + (5)/(X^-2), we need to simplify it.
First, let's deal with the negative exponents. Remember that any term with a negative exponent can be written as its reciprocal with a positive exponent.
For X^-4, we can rewrite it as 1/(X^4), and for X^-2, we can rewrite it as 1/(X^2).
Now, the expression becomes:
(6)/(1/(X^4)) + (5)/(1/(X^2))
To simplify this further, we'll use the property of dividing fractions, which is the same as multiplying by the reciprocal of the divisor.
Dividing by 1/(X^4) is the same as multiplying by (X^4)/1, and dividing by 1/(X^2) is the same as multiplying by (X^2)/1.
Applying these changes to the expression, we now have:
(6)*(X^4) + (5)*(X^2)
This simplifies to:
6X^4 + 5X^2
So, the simplified form of the expression (6)/(X^-4) + (5)/(X^-2) is 6X^4 + 5X^2.