What is the mass percent of sucrose (C12H22O11, Mm=342 g/mol) in a 0.371-m sucrose solution?
To find the mass percent of sucrose in a solution, we need to determine the mass of sucrose and the total mass of the solution.
The mass percent can be calculated using the following formula:
Mass percent = (mass of solute / mass of solution) x 100
In this case, the solute is sucrose (C12H22O11) and the solution is 0.371 m sucrose solution.
First, we need to find the mass of sucrose in the solution.
To do this, we can use the formula:
Mass = moles x molar mass
The molar mass of sucrose (C12H22O11) is 342 g/mol, given in the problem.
We are given the concentration of the sucrose solution as 0.371 m.
The concentration (molarity) can be defined as moles of solute divided by liters of solution:
Molarity (M) = moles of solute / liters of solution
Given that the concentration is 0.371 m, this means that there are 0.371 moles of sucrose in 1 liter of solution.
Next, we need to calculate the moles of sucrose in the desired volume of solution.
Since the mass percent is calculated based on the total mass of the solution, we'll assume that we have a specific mass of the solution, such as 100 g.
First, let's calculate the moles of sucrose in 1 liter of solution:
mol = concentration x volume (in liters)
Moles of sucrose = 0.371 mol/L x 1 L = 0.371 mol
To find the mass of sucrose in the solution, we can use the formula:
Mass = moles x molar mass
Mass of sucrose = 0.371 mol x 342 g/mol = 126.402 g
Now, we can calculate the mass percent using the formula:
Mass percent = (mass of solute / mass of solution) x 100
Mass of solute (sucrose) = 126.402 g
Mass of solution = 100 g (as assumed)
Mass percent = (126.402 g / 100 g) x 100 ≈ 126.402 %
Therefore, the mass percent of sucrose in the 0.371 m sucrose solution is approximately 126.402%.
To determine the mass percent of sucrose in a solution, we need to calculate the mass of sucrose present in the solution and divide it by the total mass of the solution.
Step 1: Calculate the mass of sucrose in the solution:
Mass of sucrose = concentration x volume
Given:
Concentration (molar) = 0.371 M (moles per liter)
Volume of solution = 1 liter (since the concentration is given in moles per liter)
Mass of sucrose = 0.371 moles/L x 342 g/mol x 1 L = 126.582 g
Step 2: Calculate the total mass of the solution:
Total mass of the solution = mass of sucrose + mass of water
Assuming the solution is only sucrose and water:
Mass of water = mass of solution - mass of sucrose
Assuming the solution has a density of 1 g/mL:
Mass of water = volume of solution - mass of sucrose
Given:
Volume of solution = 1 liter (1000 mL)
Mass of water = 1000 mL - 126.582 g = 873.418 g
Total mass of the solution = mass of sucrose + mass of water = 126.582 g + 873.418 g = 1000 g
Step 3: Calculate the mass percent of sucrose:
Mass percent of sucrose = (mass of sucrose / total mass of solution) x 100
Mass percent of sucrose = (126.582 g / 1000 g) x 100 = 12.66%
Therefore, the mass percent of sucrose in the 0.371-m sucrose solution is 12.66%.
.372m=mass/342)/kg of solvent
kg of solvent= 1-kgofsoute=(in grams(1000-mass)
.372*342=mass/1-mass/1000)=1000*mass/(1000-mass)
127*(1000-mass)=1000mass
127000=1000mass+127mass
mass= 127000/1127 grams or 113 grams.
check my math.