Rob is twice Joshua’s age. Nick is 5 years older than Joshua.
The sum of all their ages is 45.
How old is Nick?
Joshua - 10
Rob - 20
Nick - 15
i love maths and brian
To determine Nick's age, let's break down the information given:
1. Rob is twice Joshua's age: Let's call Joshua's age J. Rob's age is then 2J.
2. Nick is 5 years older than Joshua: Nick's age would be J + 5.
3. The sum of all their ages is 45: The equation based on all the information is J + 2J + (J + 5) = 45.
To solve this equation, we need to combine like terms:
J + 2J + J + 5 = 45
4J + 5 = 45
Now, we can isolate the variable J by subtracting 5 from both sides of the equation:
4J = 45 - 5
4J = 40
Finally, dividing both sides of the equation by 4 will give the value of J:
J = 40 / 4
J = 10
Now we can determine Nick's age by substituting J back into the equation:
Nick's age = J + 5
Nick's age = 10 + 5
Nick's age = 15
Therefore, Nick is 15 years old.
R=2*J
N-5=J
R+J+N=45
2J+J+J+5=45
4J=40
J=???