how many grams of water at 0 degree C can be frozen into ice at 0 degree C if 55.0 kJ of heat is removed?
q = mass x heat fusion
55,000 = mass x heat fusion.
Look up heat of fusion (in Joules/g) and solve for mass in grams.
To determine the amount of water that can be frozen into ice at 0 degrees Celsius, we need to calculate the heat required to freeze the water and then divide it by the heat removed.
The heat required to freeze water is known as the heat of fusion, and its value is 333.55 kJ/kg at 0 degrees Celsius.
To find the amount of water that can be frozen, we can use the following equation:
Amount of water (in grams) = Heat removed / Heat of fusion
Substituting the values:
Amount of water = 55.0 kJ / (333.55 kJ/kg)
Converting kJ to grams:
55.0 kJ = 55.0 x 1000 g
Now we can calculate the amount of water:
Amount of water (in grams) = (55.0 x 1000 g) / (333.55 kJ/kg)
Calculating this equation will give us the amount of water that can be frozen into ice at 0 degrees Celsius when 55.0 kJ of heat is removed.
To determine how many grams of water at 0 degrees Celsius can be frozen into ice at 0 degrees Celsius when 55.0 kJ of heat is removed, we need to use the concept of specific heat and heat of fusion.
Here's how we can calculate it step by step:
1. Calculate the heat of fusion:
The heat of fusion refers to the amount of heat energy required to change a substance from a solid to a liquid state. For water, the heat of fusion is 334 J/g.
2. Convert the given heat (55.0 kJ) into joules:
1 kJ = 1000 J, so 55.0 kJ = 55.0 × 1000 J = 55,000 J.
3. Using the heat of fusion, calculate the mass of water that can be frozen:
Mass = Heat energy / Heat of fusion
Mass = 55,000 J / 334 J/g
Canceling out the units, we find that:
Mass = 164.67 g
Therefore, approximately 164.67 grams of water at 0 degrees Celsius can be frozen into ice at 0 degrees Celsius when 55.0 kJ of heat is removed.