the total fare for 2 adults and 3 childrren on the Tilt a Whirl ride $14.00. If a child's fare is 1/2 of an adult's fare, what is the adult fare? we know the answer is $4 for adults and $2 for children. How do we figure this out though in 4th grade terms -no algebra yet; currently learning fractions, decimals and angles. Many thanks.
At fourth grade, I'd try trial and error.
5 + 5 + 2.50 + 2.50 + 2.50 = 17.50 -- Nope!
4 + 4 + 2 + 2 + 2 = 14 Yes!
To figure out the adult fare and child fare without using algebra, we can use a method called trial and error. Let's start by assuming the adult fare is $2.
If the adult fare is $2, then the child fare would be $1 (half the adult fare). Now, let's calculate the total fare for 2 adults and 3 children:
2 adults: 2 x $2 = $4
3 children: 3 x $1 = $3
Adding the total fare for adults and children together:
$4 + $3 = $7
However, this is not the correct total fare of $14.
Now, let's assume the adult fare is $3.
If the adult fare is $3, then the child fare would be $1.50 (half the adult fare). Now, let's calculate the total fare for 2 adults and 3 children:
2 adults: 2 x $3 = $6
3 children: 3 x $1.50 = $4.50
Adding the total fare for adults and children together:
$6 + $4.50 = $10.50
This is still not the correct total fare of $14.
Let's try assuming the adult fare is $4.
If the adult fare is $4, then the child fare would be $2 (half the adult fare). Now, let's calculate the total fare for 2 adults and 3 children:
2 adults: 2 x $4 = $8
3 children: 3 x $2 = $6
Adding the total fare for adults and children together:
$8 + $6 = $14
Finally, we have reached the correct total fare of $14. Therefore, the adult fare is $4 and the child fare is $2.