Solve the system by graphing. (Enter your answers as a comma-separated list. If the system is inconsistent, enter INCONSISTENT. If the system is dependent, enter DEPENDENT.)

x + y = 4
x − y = 2
(x, y) =

It said: Solve the system by graphing

Have you done that?

(You should be able to solve this mentally by adding the equations to verify your results from graphing)

I can not graph here

however adding the two equations
2 x + 0 = 6
so
x = 3
then
3 + y = 4
y = 1
(3,1)

To solve the system by graphing, let's first graph the equations on a coordinate plane.

For the equation x + y = 4, we can rewrite it as y = -x + 4.

For the equation x - y = 2, we can rewrite it as y = x - 2.

Now we can plot the graphs of the two equations:

For the first equation, when x = 0, y = 4. When y = 0, x = 4. So we have the points (0, 4) and (4, 0).

For the second equation, when x = 0, y = -2. When y = 0, x = 2. So we have the points (0, -2) and (2, 0).

Now let's plot these points and draw lines passing through them:

The graph of the first equation is a line passing through (0, 4) and (4, 0).
The graph of the second equation is a line passing through (0, -2) and (2, 0).

The two lines intersect at the point (2, 2).

Therefore, the solution to the system of equations is (x, y) = (2, 2).

To solve the system by graphing, we can graph each equation on the coordinate plane and see where they intersect.

For the first equation, x + y = 4, we can rearrange it to slope-intercept form as y = -x + 4. To graph this equation, we can start by plotting the y-intercept, which is 4. Then, using the slope of -1 (since -1 is the coefficient of x), we can find additional points. We can go down 1 unit and right 1 unit, which gives us the point (1, 3). Connecting these points will give us a straight line.

For the second equation, x - y = 2, we can rearrange it to slope-intercept form as y = x - 2. To graph this equation, we can start by plotting the y-intercept, which is -2. Then, using the slope of 1 (since 1 is the coefficient of x), we can find additional points. We can go up 1 unit and right 1 unit, which gives us the point (1, -1). Connecting these points will give us another straight line.

By graphing both equations, we can see where they intersect. The point of intersection represents the solution to the system. In this case, it appears that the lines intersect at the point (3, 1).

Therefore, the solution to the system is (3, 1).