Car A and Car B are separated by 4600 meters and travel toward each other. If Car A has a speed of 5 m/s and Car B has a speed of 35 m/s, how much time will pass before they pass each other?
5t + 35t = 4600m,
40t = 4600,
t = 115s. = 1.92 min.
5t + 35t = 4600m,
40t = 4600,
t = 115s. = 1.92min.
To find the time it takes for Car A and Car B to pass each other, we need to determine how long it will take for them to cover the total distance between them. We can use the formula:
Total Distance = Speed * Time
For Car A, the speed is 5 m/s, and for Car B, the speed is 35 m/s. The total distance they need to cover is 4600 meters.
So, for Car A, we have:
5 m/s * Time A = 4600 m
To find the time for Car A, we can rearrange the equation:
Time A = 4600 m / 5 m/s
Time A = 920 seconds
Similarly, for Car B, we have:
35 m/s * Time B = 4600 m
Rearranging the equation to solve for Time B:
Time B = 4600 m / 35 m/s
Time B = 131.43 seconds
The time it takes for Car A and Car B to pass each other is the maximum of Time A and Time B, which is 920 seconds (since Car A takes longer to cover the distance).
Therefore, it will take 920 seconds for Car A and Car B to pass each other.