A tennis ball with a speed of 26.3 m/s is moving perpendicular to a wall. After striking the wall, the ball rebounds in the opposite direction with a speed of 13.8338 m/s. If the ball is in contact with the wall for 0.00998 s, what is the average acceleration of the ball while it is in contact with the wall? Take “toward the wall” to be the positive direction. Answer in units of m/s2.
force*time=mass*changeinVelocity
= mass*(13.8338+26.3)=mass*(40.1)
but force= mass*acceleration
so acceleration= 40.1/.00998 m/s^2
To find the average acceleration of the ball while it is in contact with the wall, we need to use the formula:
Average acceleration = Change in velocity / Time
First, let's calculate the change in velocity. The initial velocity is 26.3 m/s, and the final velocity is -13.8338 m/s (since it's moving in the opposite direction). So the change in velocity is:
Change in velocity = Final velocity - Initial velocity
= -13.8338 m/s - 26.3 m/s
= -40.1338 m/s
Now, let's calculate the average acceleration. Given that the contact time is 0.00998 s:
Average acceleration = Change in velocity / Time
= -40.1338 m/s / 0.00998 s
= -4018.82 m/s²
Therefore, the average acceleration of the ball while it is in contact with the wall is -4018.82 m/s². The negative sign indicates that the acceleration is directed towards the wall.
To find the average acceleration of the ball while it is in contact with the wall, we can use the formula:
average acceleration = (change in velocity) / (time)
First, let's calculate the change in velocity of the ball. The initial velocity of the ball before striking the wall is 26.3 m/s, and after rebounding, the velocity becomes -13.8338 m/s. The negative sign indicates that the direction of the velocity is opposite after rebounding.
change in velocity = final velocity - initial velocity
change in velocity = -13.8338 m/s - 26.3 m/s
change in velocity = -40.1338 m/s
Next, we can substitute the values into the formula to calculate the average acceleration:
average acceleration = (-40.1338 m/s) / (0.00998 s)
Dividing these two values gives:
average acceleration ≈ -4024.82 m/s²
Therefore, the average acceleration of the ball while it is in contact with the wall is approximately -4024.82 m/s².