The halflife of Phosphorus is 14.3 days, if i start with 100g how long will it take so that only 25g will be left?
One month is my answer, I just need confirmation. Thank you
amount left=original*(1/2)^(days/14.3)
25/100=(1/2)^(days/14.3)
(1/2)^2=(1/2)^(days/14.3)
so days=28.6
Thank you
To confirm your answer, let's calculate the time it will take for the amount of Phosphorus to reduce from 100g to 25g using the given half-life of 14.3 days.
The half-life of a substance is the time it takes for half of the initial amount to decay or disappear. In this case, the half-life of Phosphorus is 14.3 days.
To calculate the time required for the amount to reduce from 100g to 25g, we need to determine how many half-lives it takes for this decay to occur.
Let's start with the initial amount of 100g:
After the first half-life, 50g of Phosphorus remains.
After the second half-life, 25g of Phosphorus remains.
Since we want to know how long it takes to reach 25g from 100g, we can conclude that it takes 2 half-lives.
Now, we multiply the half-life by the number of half-lives to calculate the total time required:
Time = Half-life x Number of Half-lives
Time = 14.3 days x 2
Time = 28.6 days
Therefore, it will take approximately 28.6 days for the amount of Phosphorus to decay from 100g to 25g.
Your answer of one month is quite close to the calculated result, considering that one month is approximately 30 days. So, your answer is confirmed to be correct.