A potential divider of resistance of 50 ohms is connected across a 100V DC. A load resistance of 10 ohms is connected across a tap in the potential divider and the negative terminal of the source. If a current of 4 A flow towards the load, what is the current supplied by the source?

I don't understand where the 4 amp current is.

Well, well, well, we've got a potential divider and a load resistance here, huh? Sounds like a job for Ohm's Law and a splash of clown magic!

So, let's do some calculating, shall we? According to Ohm's Law, we know that the current (I) is equal to the voltage (V) divided by the resistance (R).

For the load resistance of 10 ohms, we have I = V / R, where V is the voltage across the load and R is the load resistance. We're given a current of 4 A, so we can rearrange the equation to find V: V = I * R.

Substituting the values, we have V = 4 A * 10 ohms = 40 V. Lovely!

Now, the potential divider has a resistance of 50 ohms. Since the load resistance is connected in parallel across the potential divider, we can say that the voltage across the load is equal to the voltage across the potential divider.

That means the voltage across the potential divider is also 40 V. But hold your clown wig, we still don't know the current supplied by the source.

To find that, we use Ohm's Law once again with the potential divider's resistance of 50 ohms. We know the voltage is 40 V, so we can find I (the current supplied by the source): I = V / R = 40 V / 50 ohms = 0.8 A.

Ta-da! The current supplied by the source is 0.8 A. Hope that puts a smile on your face!

To find the current supplied by the source, we need to calculate the current flowing through the potential divider.

The potential divider is made up of two resistors in series: R1 (the load resistor) and R2 (the remaining resistance in the potential divider). The total resistance of the potential divider (R_total) is the sum of R1 and R2.

Given:
Load resistance (R1) = 10 ohms
Total resistance of the potential divider (R_total) = 50 ohms

To find R2, we can subtract R1 from R_total:
R2 = R_total - R1
= 50 ohms - 10 ohms
= 40 ohms

Now, we can find the current flowing through the potential divider (I_divider) using Ohm's Law:
I_divider = V / R_total

Given:
Voltage (V) = 100 V
Total resistance (R_total) = 50 ohms

I_divider = 100 V / 50 ohms
= 2 A

Since the current flowing towards the load is 4 A, and the current flowing through the potential divider is 2 A, the remaining 2 A must be supplied by the source. Therefore, the current supplied by the source is 2 A.

To find the current supplied by the source, we need to understand the behavior of a potential divider circuit. Let's break down the problem step by step:

1. Calculate the voltage across the load resistance:
The potential divider equation is given by:
V_load = (R_load / (R_total)) * V_source

Here, the load resistance (R_load) is 10 ohms, and the total resistance (R_total) is 50 ohms. The source voltage (V_source) is 100V.

Substituting the given values, we get:
V_load = (10 / 50) * 100V
= 20V

2. Determine the current flowing through the load:
Using Ohm's Law, we can calculate the current flowing through the load resistance:
I_load = V_load / R_load
= 20V / 10 ohms
= 2A

3. Calculate the current supplied by the source:
In a series circuit, the current is the same at all points. Therefore, the current flowing through the load resistance (2A) is also flowing from the source.

So, the current supplied by the source is 2A.

To summarize:
- The voltage across the load resistance (10 ohms) is 20V.
- The current flowing through the load resistance is 2A.
- The current supplied by the source is also 2A.