If (a+b)^2 = a^2 + 6b +b^2 ,what is the value of a?
Well, (a+b)^2
= a^2 + 2ab + b^2
now match up the terms with a^2 + 6b +b^2.
I don't understand what u mean by matching up the terms
a^2 + 6b +b^2 <-----> a^2 + 2ab + b^2
how about 2ab = 6b
solve for a
To find the value of a, we can start by expanding the left side of the equation using the binomial expansion formula. The formula states that (a + b)^2 = a^2 + 2ab + b^2.
Therefore, in this case, we have (a + b)^2 = a^2 + 6b + b^2.
Comparing this to the binomial expansion formula, we can see that 2ab = 6b.
Dividing both sides by 2b, we get a = 3.
So, the value of a is 3.