molarity of a solution containing
5mL of a 3.512 x 10^-5M solution
(made from .128g of benzophenone and 50mL of ethanol)
and then filled to the 50mL line of ethanol
would this be
(3.512 x 10^-5)(-.04)
?
yeah, it looks right to me.
No, this isn't correct.
3.512 M x (5 mL/50 mL) = ??
To calculate the molarity of the final solution, you need to find the number of moles of benzophenone and the final volume of the solution.
1. Start by calculating the number of moles of benzophenone using its mass and molar mass.
- The molar mass of benzophenone (C13H10O) is 182.22 g/mol.
- The mass of benzophenone is 0.128 g.
- Use the formula: moles = mass / molar mass
- Moles of benzophenone = 0.128 g / 182.22 g/mol
2. Calculate the final volume of the solution by adding the initial volume of ethanol (50 mL) to the volume of the 3.512 x 10^-5 M solution (5 mL).
- Final volume of solution = 50 mL + 5 mL
3. Now, calculate the molarity (M) of the solution using the moles of benzophenone and final volume of the solution.
- Molarity = moles / volume (in liters)
- Convert the final volume to liters by dividing by 1000 (since 1 mL = 0.001 L)
- Molarity = moles / (final volume / 1000)
Therefore, the molarity of the solution would not be (3.512 x 10^-5) x (-0.04). To obtain the correct molarity, you need to perform the above calculations using the given values.