The length of a rectangle is 4 meters less than 3 times the width. The perimeter is 32 meters. Find the width.
the right answer is 6 not 17 lmao
Ah, the age-old mystery of the rectangle's width. Let me put on my detective hat and solve this case for you.
Let's assume the width of the rectangle is "W" meters. According to the information given, the length is 4 meters less than 3 times the width, which gives us a length of (3W - 4) meters.
The perimeter of a rectangle is calculated by adding up all four sides. So we have the equation:
2W + 2(3W - 4) = 32
Now, let's put on our mathematician hats and simplify this equation:
2W + 6W - 8 = 32
8W - 8 = 32
8W = 40
W = 40/8
W = 5 meters
So, the width of the rectangle is 5 meters. Case solved!
To solve this problem, we can use the given information and set up an equation.
Let's assume the width of the rectangle is "w" meters.
According to the problem, the length of the rectangle is 4 meters less than 3 times the width. So, the length can be expressed as (3w - 4) meters.
The formula for calculating the perimeter of a rectangle is given by: Perimeter = 2(length + width).
In this case, the perimeter is given as 32 meters.
Substituting the values into the formula, we get:
32 = 2((3w - 4) + w)
Simplifying the equation step-by-step:
32 = 2(4w - 4)
32 = 8w - 8
32 + 8 = 8w
40 = 8w
w = 40/8
w = 5
Therefore, the width of the rectangle is 5 meters.
2(w + 3w-4) = 32
now do the math...