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solve the equation x^35x^24x+20=0 I need a hint on how to solve this Look for the first root by graphical means or trialanderror. Note that when x=2, x^35x^24x+20 = 820 8 +20 = 0. Therefore 2 is one root and x2 is a
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can someone help me out factor out this 0=16t^2122t+180 i have so far this but the last one i am not sure 8(2t^214t + ?) you need to use the quadratic formula: b(+or)[sqrt(b^24ac)/2a] so you are saying that i don't have to
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Factor quadratic expressions: 2x^2 + 9x + 4 10x^2 + 70x + 100 Solve quadratic equations by factoring: 2x^2 + 9x + 4 = 0 Solve by taking square roots: (x  5)^2  81 = 0
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Solve by factoring: One of the solutions to the quadratic equation x^2  13x + 30 is 3. What is the other solution? Is it:(x+3) If 3 is a solution, then the quadratic contains a factor (x3). The other factor is thus (x10), and
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solve the polynomial y=2x^24x+1 For Further Reading algebra  Reiny, Thursday, May 17, 2007 at 10:34pm I am sure neither your text nor your teacher asked you to "solve the polynomial y=2x^24x+1 " are you graphing the function,
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x^3 + 1.85x^2  x +0.15 = 0 how can you solve for x? An exact solution or a numerical solution? Exact solutions can be obtained as follows: x^3  1.85x^2 + x  0.15 = 0 First get rid of the quadratic term by substituting: x = (y
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i also have theses to solve Factor the polynomial x2 + 5x + 6 completely Solve the given equation by using the quadratic formula. x2 – 7x – 4 = 0 What value is under the square root (or radical) in your answer? (Note: You are
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How can I find the point of intersection of the graphs x^2=y=4 and 2xy=1 by hand? I can do the problem using a calculator, but I don't know how to do it by hand. I tried using substitution, but I ending up getting x^2+2x5=0. It
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Why are there two solutions in the quadratic equation and Why do you factor a quadratic equation before you solve it
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Find the polynomials roots to each of the following problems: #1) x^2+3x+1 #2) x^2+4x+3=0 #3) 2x^2+4x5 #3 is not an equation. Dod you omit "= 0" at the end? #2 can be factored into (x+1)(x+3) = 0, so the roots are x=1 and 3.
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algebra
solve for x (24+2x)(10+2x)  240 = 152 First multiply. 24(10) = ___ 2x (2x) = ____ Now subtract 240. Can you finish the problem from here? dont i need to put this in equatic equation to solve for x. cause i need to find the width
asked by q on August 3, 2007