A jetliner flies west 2,000 miles from Chicago you San Francisco. It has an average speed of 635 mph relative to the air. What is the velocity of the jetliner relative to the earth of the wind is blowing at 160 mph from the west to the east?
475 mph, east
475 mph, west(my guess)
795 mph, west
795 mph, east
A hot air ballon rises vertically at a constant rate of 8 m/s. A second hot air balloon descends passed the first hot air balloon at rate of 12 m/s relative to the first hot air balloon. What is the velocity of the second hot air ballon relative to the ground?
4 m/s, Up
20 m/s. Up
4 m/s, down
20 m/s, down(my guess)
To solve the first problem, you need to consider the velocity of the jetliner relative to the ground. The velocity of the jetliner relative to the ground will be the sum of its velocity relative to the air and the velocity of the wind.
Since the wind is blowing from the west to the east (opposite direction of the jetliner), you need to subtract the velocity of the wind from the velocity of the jetliner relative to the air.
Given:
Velocity of the jetliner relative to the air = 635 mph (west)
Velocity of the wind = 160 mph (east)
To determine the velocity of the jetliner relative to the ground, subtract the velocity of the wind from the velocity of the jetliner relative to the air:
635 mph (west) - 160 mph (east) = 475 mph (west)
Therefore, the velocity of the jetliner relative to the earth is 475 mph, west.
For the second problem, you need to determine the velocity of the second hot air balloon relative to the ground. To do this, you need to consider the relative velocities of the two hot air balloons.
Given:
Velocity of the first hot air balloon (ascending) = 8 m/s (up)
Velocity of the second hot air balloon (descending) relative to the first hot air balloon = 12 m/s (down)
To determine the velocity of the second hot air balloon relative to the ground, subtract the velocity of the first hot air balloon (ascending) from the velocity of the second hot air balloon (descending):
12 m/s (down) - 8 m/s (up) = 4 m/s (down)
Therefore, the velocity of the second hot air balloon relative to the ground is 4 m/s, down.