A jetliner flies west 2,000 miles from Chicago you San Francisco. It has an average speed of 635 mph relative to the air. What is the velocity of the jetliner relative to the earth of the wind is blowing at 160 mph from the west to the east?
475 mph, east
475 mph, west
795 mph, west(my guess)
795 mph, east
A hot air ballon rises vertically at a constant rate of 8 m/s. A second hot air balloon descends passed the first hot air balloon at rate of 12 m/s relative to the first hot air balloon. What is the velocity of the second hot air ballon relative to the ground?
4 m/s, Up
20 m/s. Up
4 m/s, down(my guess)
20 m/s, down
Can you please explain how to get the answer and if I’m wrong or correct?
To find the velocity of the jetliner relative to the earth, we need to consider the effect of the wind. The speed of the jetliner relative to the earth is the difference between its speed relative to the air and the speed of the wind.
The average speed of the jetliner relative to the air is given as 635 mph. The wind is blowing at 160 mph from the west to the east. Since the jetliner is flying west, we need to subtract the speed of the wind from its speed relative to the air.
So, the velocity of the jetliner relative to the earth is 635 mph (jetliner's speed relative to the air) - 160 mph (wind speed from west to east) = 475 mph. Since the wind is blowing from the west to the east, the velocity of the jetliner relative to the earth is 475 mph, east. Therefore, your guess of 795 mph west is incorrect.
For the second question, let's use the concept of relative velocity. The first hot air balloon is rising vertically at a constant rate of 8 m/s.
Now, let's consider the second hot air balloon relative to the first one. The second hot air balloon is descending at a rate of 12 m/s relative to the first hot air balloon. Since the first hot air balloon is rising, we subtract the descending velocity of the second balloon from the rising velocity of the first balloon.
So, the velocity of the second hot air balloon relative to the first balloon is 8 m/s (rising velocity of the first balloon) - 12 m/s (descending velocity of the second balloon) = -4 m/s. The negative sign indicates the direction of downward motion.
Since we need to find the velocity of the second hot air balloon relative to the ground, we take into account that the first balloon is rising vertically, not moving horizontally. Therefore, the velocity of the second hot air balloon relative to the ground is the same as its velocity relative to the first balloon, which is -4 m/s, downward.
Based on this, your guess of 4 m/s down is correct for the velocity of the second hot air balloon relative to the ground.