Mrs. Daniel pays $324 for a handbag and 3 pairs of shoes. The handbag costs half as much as the 3 pairs of shoes combined. Find the cost of the handbag.
324=H+3S
H=.5(3S)
324=.5(3S)+3S
4.5S=324
Shoes=324/4.5
can you handle it from here?
I think you do so do sowe first you do we know that it 324 for a handbag and 3 pair of shoe. The handbag costs half as much 3 pair of shoe. The awesner is 108
To find the cost of the handbag, let's assign variables to the unknowns in the problem.
Let's say the cost of the handbag is "H" and the cost of each pair of shoes is "S."
According to the problem, Mrs. Daniel pays $324 for the handbag and 3 pairs of shoes. This can be expressed as:
H + 3S = $324 ---(Equation 1)
The problem also tells us that the cost of the handbag is half the cost of the three pairs of shoes combined. So, we can write this relationship as:
H = (1/2)(3S)
H = 1.5S ---(Equation 2)
Now we have a system of two equations. We can solve this system of equations to find the values of H and S.
Substitute Equation 2 into Equation 1, we get:
1.5S + 3S = $324
Combine like terms:
4.5S = $324
Divide both sides by 4.5:
S = $72
Now we have the value of S, which represents the cost of each pair of shoes.
Substitute the value of S back into Equation 2:
H = 1.5S
H = 1.5($72)
H = $108
Therefore, the cost of the handbag is $108.