A man whose mass is 80kg stands on a spring weighing machine inside an elevator. What is the readingof the weighing machine when
and.....???
weight reading=80(9.8 +- acceleration) + is going up, - going down.
To find the reading of the weighing machine when the elevator is at rest, we need to consider the forces acting on the man.
When the elevator is at rest, the man experiences two forces:
1. The force due to gravity pulling the man downward, given by the equation Fg = mg, where m is the mass of the man and g is the acceleration due to gravity (approximately 9.8 m/s²).
2. The force exerted by the spring weighing machine, which opposes the force of gravity.
At rest, these two forces are balanced, meaning they are equal in magnitude but opposite in direction. Therefore, the reading of the weighing machine is equal to the force exerted by gravity.
Using the equation Fg = mg, where m is the mass of the man (80 kg), and g is the acceleration due to gravity (9.8 m/s²), we can calculate the force due to gravity:
Fg = 80 kg * 9.8 m/s² = 784 Newtons
Therefore, the reading of the weighing machine when the elevator is at rest is 784 Newtons.