How would you write a skeleton equation for these reactions I always get confused
nickel(II)chloride(s)+oxygen(g)= nickel (II) oxide(s) +dichlorine pentaoxide (g)
lithium chromate(aq)+barium chloride(aq)= lithium chloride(aq)+barium chormate(s)
Lauren: See the link on the other post. Go over the basics for writing chemical formulas, and give it a whack. Stop this answer grazing, you can do better than that. We will be happy to check you.
To write skeleton equations for these reactions, we need to remember a few key steps:
Step 1: Identify the reactants and products.
In the first reaction:
Reactants: nickel(II) chloride and oxygen
Products: nickel(II) oxide and dichlorine pentoxide
In the second reaction:
Reactants: lithium chromate and barium chloride
Products: lithium chloride and barium chromate
Step 2: Write the formula for each substance.
Let's start with the first reaction:
Reactants: Nickel(II) chloride is represented by the chemical formula NiCl2, and oxygen is represented by O2.
Products: Nickel(II) oxide is represented by NiO, and dichlorine pentoxide is represented by Cl2O5.
Therefore, the skeleton equation for the first reaction is:
NiCl2(s) + O2(g) -> NiO(s) + Cl2O5(g)
Now, moving on to the second reaction:
Reactants: Lithium chromate is represented by Li2CrO4, and barium chloride is represented by BaCl2.
Products: Lithium chloride is represented by LiCl, and barium chromate is represented by BaCrO4.
Therefore, the skeleton equation for the second reaction is:
Li2CrO4(aq) + BaCl2(aq) -> LiCl(aq) + BaCrO4(s)
Note that (s) stands for solid, (g) stands for gas, and (aq) stands for an aqueous solution.
In summary:
1st reaction: NiCl2(s) + O2(g) -> NiO(s) + Cl2O5(g)
2nd reaction: Li2CrO4(aq) + BaCl2(aq) -> LiCl(aq) + BaCrO4(s)
Now you have the skeleton equations for both reactions!